electromagnetism Does ratio of magnetic length to geometric length of

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DC magnetic data for 1 a Effective magnetic moment inset low

The effective length of a magnet is $31.4 \mathrm{~cm}$ and its pole strength is $0.8 \mathrm{Am}$. The magnetic moment, if it is bent in the form of a semicircle is.

electromagnetism Does ratio of magnetic length to geometric length of

The effective length of a magnet is 31.4 cm and its pole strength is 0.5Am. Calculate its magnetic moment. If it is bent in form of semicircle, then magnetic moment will be A 0.157Am2,0.01Am2 B 0.357Am2,0.01Am2 C 1.157Am2,1.01Am2 D None of these Difficulty level: medium Viewed by: 5,764 students Solutions ( 1)

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The effective length of a magnet is 31.4 cm and its pole strength is 0.8 Am. The magnetic moment, if it is bent in the form of a semicircle is _____ Am 2. A 1.2 B 1.6 C 0.16 D 0.12 Easy Solution Verified by Toppr Correct option is C) The effective length of magnet =31.4 cm Pole strength m=0.8 Am Length of semi-circle =π 2D=l

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The effective length of a magnet is 31.4 cm and its pole strength is 0.5 Am. The magnetic moment, if it is bent in the form of a semicircle will be A 0.1 Am2 B 0.01 Am2 C 0.2 Am2 D 1.2 Am2 Solution The correct option is C 0.1 Am2 Similar to solution (1) New magnetic moment M = 2M π = 2mL π = 2×0.5×31.4×10−2 3.14 =0.1 amp×m2 Suggest Corrections 9

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Here you can find the meaning of The effective length of a magnet is 31.4 cm, and its pole strength is 0.5 A-m. If it is bent in the form of a semicircle,then its new magnetic moment will bea)0.2 A-m2b)0.1 A-m2c)0.05 A-m2d)0.01 A-m2Correct answer is option ‘B’.

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No views 1 minute ago The effective length of a magnet is \ ( 31.4 \mathrm {~cm} \) and its pole strength is \ ( 0.5 \mathrm {Am} \). The magnetic moment, if it is bent in the form of a.

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The effective length of a magnet is 31.4 cm and its pole strenth is 0.5 Am. Doubtnut 2.73M subscribers Subscribe 372 views 3 years ago The effective length of a magnet is 31.4.

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The effective length of a magnet is 31.4 cm and its pole strength is 0.8 Am. The magnetic moment, if it is bent in the form of a semi circle is Moderate A 1.6 B 1.2 C 0.16 D 0.12 Solution M ‘ = 2 M π = 2 × 2 l × m π = 2 × 31.4 × 10 − 2 × 0.8 3.14 = 0.16 Get Instant Solutions When in doubt download our app.

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The effective length of a magnet is 31.4 c m and its pole strength is 0.5 A m. The magnetic moment, if it is bent in the form of a semicircle will be The magnetic moment, if it is bent in the form of a semicircle will be

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The effective length of a magnet is 31.4 cm and. its pole strength is 0.5 Am. If it is bent in the form of semicircle, what will be its magnetic moment then ? Q. The effective length of a magnet is 31.4cmand. its pole strength is 0.5Am. If it is bent in the form of semicircle, what will be its magnetic moment then ? 1454 72

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Effective length = 2R = 2L/pi Magnetic moment = 2 * 0.314 * 0.5 /3.14 = 0.1 Am 2 Hope it helps Regards Arun Khimraj 3007 Points 3 years ago Magnetic moment = M = pole strength × effective length = 0.5 × 31.4 × 10-2 = 15.7 × 10-2 Am2 when bent in semicircle, new magnetic moment = M’ = (2M/π) ∴ M’ = [ (2 × 15.7 × 10-2)/ (3.14)] = 0.1 Am2

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The effective length of a magnet is 31.4cm and its pole strength is 0.5Am. The magnetic moment, if it is bent in the form of a semicircle will be A 0.1Am 2 B 0.01Am 2 C 0.2Am 2 D 1.2Am 2 Medium Solution Verified by Toppr Correct option is A) Magnetic moment = M = pole strength × effective length = 0.5×31.4×10 -2=15.7× 10-2A.m 2

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The distance between the effective magnetic poles of a magnet. Also known as equivalent magnetic length.

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Answered step-by-step The effective length of a magnet is 31.4 c m and its pole strength is 0.5 A m. The magnetic moment, if it is bent in the form of a semicircle will be Amp.m 2 (a) 0.1 (b) 0.01 (c) 0.2 (d) 1.2 Video Answer Solved by verified expert Oh no! Our educators are currently working hard solving this question.

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Correct option is C The effective length of magnet Pole strength Length of semi-circle where, diameter of circle Now, the magnetic moment

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Now we can substitute all the given values from the question in the above equation. Given that the effective length of the magnet l = 31.4 c m = 31.4 × 10 − 2 m The pole strength of the magnet m = 0.8 A m Therefore we get, M = 0.8 × 2 × 31.4 × 10 − 2 3.14 Solving the above equation we get, M = 0.16 A m 2